Author Topic: Homework Help/Tutoring (Read 12985 times)

bananabrain · « **Reply #40 on:** September 28, 2007, 11:45:39 AM »

yootz look at my last post on thread and help please.

KnacK · « **Reply #41 on:** September 28, 2007, 12:43:43 PM »

d.

z>x

x=5/2
y=5/2
z=3

y00tz · « **Reply #42 on:** September 28, 2007, 12:52:23 PM »

Quote

if 2x over three =5,2y-2 over 4 =3,and z over 2 +z over 3=5 which of the following is true

2X/3 = 5

2X = 5(3)

2x = 15

X = 15/2

(2Y-2)/4 = 3

2Y-2 = 3(4)

2Y-2 = 12

2Y = 14

Y=7

Z/2 + Z/3 = 5

3Z/6 + 2Z/6 = 5

5Z = 5(6)

Z = 6

_______________

A. X>Y

KnacK · « **Reply #43 on:** September 28, 2007, 01:14:09 PM »

omg I see the error of my ways

bananabrain · « **Reply #44 on:** October 01, 2007, 11:54:24 AM »

Thank you for the help.As for you knack I think you should go back to school..LOL by

atmays · « **Reply #45 on:** October 01, 2007, 12:25:38 PM »

Ok I just need to learn calc and trig I would be straight.

I need to know this for what im goin into

ViciouZ · « **Reply #46 on:** October 01, 2007, 12:28:50 PM »

Is there some kind of higher level trigonometery because I learnt it a year ago...

y00tz · « **Reply #47 on:** October 01, 2007, 12:37:58 PM »

It can get more complex (see pre-calc with limits)

But I think I learned trig as a 7th grader here in The States.

SmackWaters · « **Reply #48 on:** October 08, 2007, 01:04:49 PM »

xy – a = ax + y How do you solve that for x? Would it be x = (ax + y) + a) / y?

ViciouZ · « **Reply #49 on:** October 08, 2007, 01:18:00 PM »

xy -a = ax + y

x = (a + ax + y) / y is what I get. But I'm probably wrong.

SmackWaters · « **Reply #50 on:** October 08, 2007, 01:28:27 PM »

Well, it depends. Do you divide the y or add the a first? I can't remember.

nopyo · « **Reply #51 on:** October 08, 2007, 01:44:56 PM »

add the a 1st. trust me, I'm Asian.

DaRkNeSS · « **Reply #52 on:** December 20, 2007, 11:57:45 PM »

Simplify:

1-csc x
csc x

sin²u x cot²u + sin²u

sin(x-(pie/6))

tan7u + tan5u
1-tan7u x tan5x

Any type of showing steps shown would be wonderful.

DaRkNeSS · « **Reply #53 on:** December 21, 2007, 12:02:21 AM »

Given:

Cos x = (2/3) and 3pie/2<x<2pie, find cos(x/2)

sk89q · « **Reply #54 on:** December 21, 2007, 01:28:52 AM »

Only going to do the first one since I'm reading a book.

Just change csc(x) to 1/sin(x), and then you've got a fraction over a fraction. The rest should be algebra -- no more identities needed.

DaRkNeSS · « **Reply #55 on:** December 21, 2007, 01:44:13 AM »

Thanks.

sk89q · « **Reply #56 on:** December 21, 2007, 02:06:21 AM »

Okay, second one:

sin^2(u)(cot^2(u)+1) -- distributive property

Then, change cot^2(u) to cos^2(u)/sin^2(u), use some algebra to un/re-distribute it, sin^2(u) should cancel on the first term (the fraction), and then use the identity cos^2(u)+sin^2(u) = 1

Third one, I guess you could use the sum/difference identities, but I don't know if that really counts as simplifying. (sin(u-v)=sin(u)cos(v)-cos(u)sin(v))

Fourth looks like a royal bastard and I don't see a way to do it easily off my head.

And fifth, it's been too long since I've done trig and it's too late for me to try too hard.

eradicator · « **Reply #57 on:** January 28, 2008, 07:29:33 PM »

K I need some french help. I am a standard French level two student and I need help with some easy sentences.
let me know if you can help and dont use a translator i really need help.
ill post the sentences when i find one of you who can help. prefrebly someone who is fluent in francais.
-erad

magalhaes · « **Reply #58 on:** January 28, 2008, 07:32:17 PM »

Most of the people who are fluent in french are far away from fluent in english so...=\

Garrett · « **Reply #59 on:** January 28, 2008, 07:46:26 PM »

Quote from: DaRkNeSS on August 25, 2007, 12:27:41 AM

y00tz you should make an IRC channel for people to get homework help, so they can play even MORE DP.

I like this idea too. I am pretty good in alg too.